How much work will be done in enlarging the surface area of a soap bubble by 1.0 cm2? Surface tension of soap solution is 1.8 x 10-2 N m-1..
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Given:
Surface area = + 1 cm^2
Surface tension = 1.8 * 10^-2 N / m
To find:
Work done.
Solution:
Change in area = 1 * 2
Change in area = 2 sq.cm
Work done = Surface tension * change in area
Substituting,
We get,
1.8 * 10^-2 * 2
Work done = 3.6 * 10^-6 J
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