Physics, asked by eknoor1503, 1 year ago

How much work will be done in enlarging the surface area of a soap bubble by 1.0 cm2? Surface tension of soap solution is 1.8 x 10-2 N m-1..

Answers

Answered by topanswers
16

Given:

Surface area = + 1 cm^2

Surface tension = 1.8 * 10^-2 N / m

To find:

Work done.

Solution:

Change in area = 1 * 2

Change in area = 2 sq.cm

Work done = Surface tension * change in area

Substituting,

We get,

1.8 * 10^-2 * 2

Work done = 3.6 * 10^-6 J

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