how much work will be done in increasing the radius of a soap bubble from 1 cm to 5 cm is (surface tension equal to 73 x10^2 N/m.)
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Work done = surface tension × increase in area
= 73×10^2 × 4pi(R^2-r^2)
=73 ×10^2 × 4 ×3.14 (24)/100 m
= 22005.12 j
= 73×10^2 × 4pi(R^2-r^2)
=73 ×10^2 × 4 ×3.14 (24)/100 m
= 22005.12 j
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