Question

How o solve log(225÷32)-log(25÷81)+log(64÷729)

Answer 1

Given log(225/32) - log(25/81) + log(64/729).

We know that log a - log b = log (a/b)

log(225/32) = log (225/32/25/81) + log(64/729)

                    = log (729/32) + log(64/729)

We know that log a + log b = log ab.

                     = log(729/32 * log 64/729)

                    = log 2.


Hope this helps!


The value is 10 base log 2.

Answer 2

this is the solution for ur log question