Math, asked by anuritha, 1 year ago

find the remainder when 26(26^2+20)+(37^2-37) is divided by 48 .the person who answer will be consider as brainly


juttuc4: it is "CONSIDERED"
aqibshaikh: thanks for that.....

Answers

Answered by aqibshaikh
3
= 26(676+20)+(1369-37)
= 26(696)+1332
= 18096+1332
= 19428

divided by 48

= 19428/48
= 404.75

answer is 404.75

anuritha: Sorry for the spelling mistake
aqibshaikh: yes its ok
aqibshaikh: give me some time i will solve it for u
anuritha: And it is my mistake it is (37^5-37)
aqibshaikh: oh
aqibshaikh: write the full question again here
anuritha: Yes i am sorry
aqibshaikh: plz
anuritha: Find the remainderwhen 26(26^2+20)+(37^5-37 ) is diveded by 48
anuritha: Thank you for all
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