How should I calculate the equivalent resistance of the following circuit:
Answers
First, 10Ω and 8Ω resistor are in series so we will get an equivalent resistor of 18Ω.
Then, 9Ω and 18Ω resistors are in parallel so we will get an equivalent resistor of 6Ω.
Then, 14Ω and 6Ω resistors are in series so we get an equivalent resistor of 20Ω.
On the other side, 5Ω and 15Ω resistors are in series so again we get an equivalent resistor of 20Ω.
Now, Both the 20Ω resistors on the right side are in parallel so we get an equivalent resistor of 10Ω.
Then, 10Ω and 6Ω resistor are in series so we get an equivalent resistor of 16Ω.
Then, 16Ω and 48Ω resistors are in parallel so we get an equivalent resistor of 12Ω.
Finally, 20Ω from the left and 12Ω resistor from the right are in series so at last we get an equivalent resistor of 32Ω.
Hope it helps.
Thanks!!!