Question

how should we solve applications of trigonometry questions ​

Answer 1

Step-by-step explanation:

Breadth of rectangle is 18 m.

Area of rectangle is 360 m².

Step-by-step explanation:

Given:-

Perimeter of rectangle is 76 m.

Length of rectangle is 20 m.

To find:-

Breadth of rectangle.

Area of rectangle.

Solution:-

Let, Breadth of rectangle be x.

Perimeter of rectangle = 2(l + b)

So,

Put the values in formula:

\longrightarrow⟶ 76 = 2×(20 + x)

\longrightarrow⟶ 76 = 40 + 2x

\longrightarrow⟶ 76 - 40 = 2x

\longrightarrow⟶ 36 = 2x

\longrightarrow⟶ 36/2 = x

\longrightarrow⟶ x = 18

Verification:-

\longrightarrow⟶ 76 = 2×(20 + x)

Put x = 18

\longrightarrow⟶ 76 = 2×(20 + 18)

\longrightarrow⟶ 76 = 40 + 36

\longrightarrow⟶ 76 = 76

\boxed{\sf Hence \: Verified.}

HenceVerified.

We have taken,

Breadth be x

So,

Breadth of rectangle is 18 m.

Now,

We know,

Area of rectangle = Length × Breadth

\longrightarrow⟶ 20 × 18

\longrightarrow⟶ 360

Therefore,

Area of rectangle is 360 m².

Answer 2

Answer:

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