Question

How should you arrange five 3 ohms resistors so that a total of 7 ohms is obtained?​

Answer 1

Answer:

you will get minimum 3Ω, & maximum 27Ω. Now I’m explaining whole possible answers.

Explanation:

possibility 1: Three 9Ω resistors are in parallel connection.

INV((1/9) + (1/9) + (1/9)) = 3Ω

possibility 2: Two 9Ω resistors are in parallel with one 9Ω in series connection.

INV((1/9) + (1/9)) + 9 = 13.5Ω

possibility 3: Two 9Ω resistors are in series with one 9Ω in parallel connection.

INV((1/(9+9)) + (1/9)) = 6Ω

possibility 4: Three 9Ω are in series connection.

9+9+9 = 27Ω

So, in no way we can get a equivalent of 12Ω resistance