how the find the hybridisation of NO4+ its answer is sp3
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Answered by
5
here we can use the formula 1/2 (N+B-C)... where N is number of valence electron in central atom....b is no atoms surrounding it and c is the charge on atom...
Hence 1/2 (5+4-1)=1/2 * 8 =4
and hence hybridisation is sp3...
Regards
Hence 1/2 (5+4-1)=1/2 * 8 =4
and hence hybridisation is sp3...
Regards
Buddh:
plz mrk brainliest if u lyk d answer
there is no formula like this
there is formula my frnd....in which class u r??
Answered by
4
i want to give you a tips for your question.
as we know the valence electron of nitrogen is 5 and we have one positive sign so,
5 - 1= 4.
we dont need to count the valence electron of oxygen.
therefore as the answer is 4, its hybridisation is sp3.
practice it by using this tips.. hope you will like it.
as we know the valence electron of nitrogen is 5 and we have one positive sign so,
5 - 1= 4.
we dont need to count the valence electron of oxygen.
therefore as the answer is 4, its hybridisation is sp3.
practice it by using this tips.. hope you will like it.
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