Question

how to add 3a2b2-4ab+5, 8a2b2+12ab-9, 15-6ab-5a2b2

Answer 1

Answer:

3a²b²-4ab+5+8a²b²+12ab-9+15-6ab-5a²b²

3a²b²+8a²b²-5a²b²-4ab+12ab-6ab+5-9+15

11a²b²-5a²b²-4ab+6ab-4+15

6a²b²+2ab+11

Answer 2

Given,

3a²b²-4ab+5, 8a²b²+12ab-9, and 15-6ab-5a²b²

To find,

The value of 3a²b²-4ab+5, 8a²b²+12ab-9, and 15-6ab-5a²b² after addition.

Solution,

The value of 3a²b²-4ab+5, 8a²b²+12ab-9, and 15-6ab-5a²b² after addition will be 6a²b²+2ab+11.

We can easily solve this problem by following the given steps.

First, let's put the sign of addition between these three expressions.

Then, we have

(3a²b²-4ab+5) + (8a²b²+12ab-9) + (15-6ab-5a²b²)

Multiplying the sign of addition into the brackets, we get

3a²b²-4ab+5 + 8a²b²+12ab-9 + 15-6ab-5a²b²

Now, the numbers with the same variables will get added or subtracted.

So, putting the numbers with the same variables in one bracket, we will have

(3a²b²+8a²b²-5a²b²) + (-4ab+12ab-6ab) + (5-9+15)

Adding the numbers with the same sign in the brackets,

(11a²b²-5a²b²) + (12ab-10ab) + (20-9)

6a²b²+2ab+11

Hence, the value of 3a²b²-4ab+5, 8a²b²+12ab-9, and 15-6ab-5a²b² after addition will be 6a²b²+2ab+11.