how to add the consequetive no. up to 100
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formula for the sum of first consecutive "n"natural Numbers
= n(n+1)/2
here n= 100
= 100 (100+1) /2
= 100 ×101 /2
= 50 ×101 = 5050
hence ,the sum of first 100 consecutive natural Numbers =5050
hope it helps !
thank you !
= n(n+1)/2
here n= 100
= 100 (100+1) /2
= 100 ×101 /2
= 50 ×101 = 5050
hence ,the sum of first 100 consecutive natural Numbers =5050
hope it helps !
thank you !
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