Question

How to answer this?
$x^{2} +x-4=2$

Answer 1

$x^{2} +x-4=2$
$x^{2} +x-6=0$
$x^{2} +3x-2x-6$
$x(x+3)-2(x+3)$
$(x-2)(x+3)$
$x=2 , x=-3$

Answer 2

x² + x - 4 - 2 = 0
x² + x - 6 = 0
( two numbers which add up to give 1 and multiplied to give - 6 is 3 and -2)
x² + 3x - 2x - 6 = 0
x(x + 3) - 2 (x + 3) = 0
(x + 3) (x - 2) = 0
x = -3 , 2