How to balance a chemical equation steps with examples?
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1st) write an unbalanced equation,using the correct formulas for all reactants and products.
2nd) Add appreciate coefficients to balance the numbers of atoms of each element.
e.g. H2SO4+NaOH--Na2SO4+H2O(unbalanced)
H2SO4+2NaOH
add this coefficient (2)--Na2SO4+H2O
to balance these 2Na(balanced for Na)
2nd) Add appreciate coefficients to balance the numbers of atoms of each element.
e.g. H2SO4+NaOH--Na2SO4+H2O(unbalanced)
H2SO4+2NaOH
add this coefficient (2)--Na2SO4+H2O
to balance these 2Na(balanced for Na)
Answered by
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firstly let's take two events magnesium,oxygen
when we are burning magnesium ribbion in the presence of oxygen it forms magnesium oxide.chemically it can be written as
Mg+O2 ------>MgO
now in the above equation left side ones(Mg,I) are called reactants
right side one(MgO) called products.
so write reactants on left side and products on right side.
reactants side/LHS product side/RHS
Mg. 1 Mg1
O. 2 O 1
here oxygen is not balanced so to make it equal multiply with 2
Mg.1 Mg 1
O 2 O 1×2
now let me write equation based on this
Mg+O2---------->2MgO
here MgO is a compound so we can't write 2 as O2. so I wrote it at first.
now magnesium also became 2 along with oxygen .
the final step is multiply ×2 on both reactants and products side.
so the final balanced chemical equation will be 2Mg+O2---------->2MgO.
hope u understood by now.
when we are burning magnesium ribbion in the presence of oxygen it forms magnesium oxide.chemically it can be written as
Mg+O2 ------>MgO
now in the above equation left side ones(Mg,I) are called reactants
right side one(MgO) called products.
so write reactants on left side and products on right side.
reactants side/LHS product side/RHS
Mg. 1 Mg1
O. 2 O 1
here oxygen is not balanced so to make it equal multiply with 2
Mg.1 Mg 1
O 2 O 1×2
now let me write equation based on this
Mg+O2---------->2MgO
here MgO is a compound so we can't write 2 as O2. so I wrote it at first.
now magnesium also became 2 along with oxygen .
the final step is multiply ×2 on both reactants and products side.
so the final balanced chemical equation will be 2Mg+O2---------->2MgO.
hope u understood by now.
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