How to calculate 18M H2SO4 Solution?
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We use the relationship: concentration=Moles of soluteVolume of solution, and get under 100⋅mL of conc. acid.
Explanation:
We require 250⋅mL of a 6.0⋅mol⋅L−1solution (with respect to H2SO4).
With respect to H2SO4, this represents a molar quantity of 0.250⋅L×6.0⋅mol⋅L−1=1.50⋅mol.
If the mother solution has a 18⋅mol⋅L−1concentration, then we solve the quotient, 1.50⋅mol18⋅mol⋅L−1×1000⋅mL⋅L−1=??⋅mL.
Alternatively we could use the following formula for the molar equivalence:
C1V1=C2V2
Important, so get it right
WHEN YOU DO THESE DILUTIONS YOU ALWAYS ADD
ACID TO WATER!!!!
Why? BECAUSE IF YOU SPIT IN ACID IT SPITS BACK AT YOU. I am not joking.
Explanation:
We require 250⋅mL of a 6.0⋅mol⋅L−1solution (with respect to H2SO4).
With respect to H2SO4, this represents a molar quantity of 0.250⋅L×6.0⋅mol⋅L−1=1.50⋅mol.
If the mother solution has a 18⋅mol⋅L−1concentration, then we solve the quotient, 1.50⋅mol18⋅mol⋅L−1×1000⋅mL⋅L−1=??⋅mL.
Alternatively we could use the following formula for the molar equivalence:
C1V1=C2V2
Important, so get it right
WHEN YOU DO THESE DILUTIONS YOU ALWAYS ADD
ACID TO WATER!!!!
Why? BECAUSE IF YOU SPIT IN ACID IT SPITS BACK AT YOU. I am not joking.
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