How to calculate atoms of a sulphur of 6.4g??
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According to Avogadro's law
32 g sulphur consists of 6.02*10^23 atoms
therefore 6.4 g consists = 6.02*10^23 * 6.4 = 1.202 * 10^22 atoms
32
^ indicates to the power of
32 g sulphur consists of 6.02*10^23 atoms
therefore 6.4 g consists = 6.02*10^23 * 6.4 = 1.202 * 10^22 atoms
32
^ indicates to the power of
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