how to calculate distance from B to Q
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Pythagoras theorem and perpendicular
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Construct perpendicular AD
it is an equilateral triangle so perpendicular is also the side n angle bisecter
Now, BD= a/2
Q is the centroid of an equilateral triangle so AQ:QD = 2:1
AQ = √a² - a²/4
AQ = a√3/2
so, QD = a√3/4
Now, BQ = √a²/4 + 3a²/16
BQ = √7a²/16
BQ = a√7/4
This is ur ans....
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BruceEvergreen:
sorry bro its answer is a/root3
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