Question

how to calculate it in very briefly

Answer 1

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the first equation will be >>
$\underline \frak{x - 5 =3(y - 5) } \\ > > \frak{x - 5 = 3y - 15} \\ > > \frak{x - 3y = - 15 + 5} \\ > > \frak{x - 3y = - 10 \: we \: obtain \: the} \\ \frak{ \: first \: equation \: here \: then \: we \: go \: to \: next } \\ \underline{\frak{x + 10 = 2(y + 10)}} \\ > > \frak{x + 10 = 2y + 20} \\ > > \frak{x - 2y = 20 - 10} \\ > > \frak{x - 2y = 10 \: now \: we \: got \: second one} \\ > > \mathcal{BY \: USING \: ELIMINATION } \\ \mathcal{ METHOD = > } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frak{x - 3y = - 10} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frak{x + 2y = 10} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - \: \: - \: \: \: \: \: - \\ \: \: \: \: \: \: \: \: \: \: \: \: - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \frak{ - 5y = - 20} \\ \frak{the \: minus \: and \: minus \: will \: be \: cancelled} \\ \frak{5y = 20, \: y = \frac{20}{5} = 4 \: now \: we \: have } \\ \frak{y = 4 \: we \: have \: to \: find \: x \: also\: hence, \: } \\ \frak{putting \: the \: value \: of \: y \: on \: first \: equation} \\ > > \underline\frak{x - 3y = - 10} \\ > > \frak{x \: - 3(4) = - 10} \\ \frak{x - 12 = - 10, \: x = - 10 + 12 = 2} \\ \frak{now, \: we \: have \: both \: x \: and \: y \: are \: = > } \\ \frak{y = 4, \:x = 2 } \\ \frak{the\: age \:of \:Shakeel \: } \\ \frak{x+10=2(y+10)}\\ \frak{X+10=2y+20}\\ \frak{x+10=2×4+20}\\ \frak{X=28-10=18}\\ \frak{so the\: mr. shakeel\: is \:18\: years\: old}$
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