Question

how to calculate mass of 6.022*1023 molecules of caco3

Answer 1

$6.022*10^{23}$ molecules are equal to 1Mole

1Mole of $CaCO_{3}$ has mass of 100g (mass of Calcium + mass of Carbon + 3 times the mass of Oxygen)

Therefore, $6.022*10^{23}$ molecules of $CaCO_{3}$ has mass 100g

Answer 2

Hope it helps......