How to calculate oxidation state of oxides of nitrogen?
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1
WE CAN CALCULATE BY THE FOLLOWING WAY
FOR EXAMPLE
NO2 = OXIDATION STATE OF NITROGEN + 2* OXIDATION OF OXYGEN = 0 ( IT IS A RULE )
N + 2*(-2)=0
N - 4=0
N=4
THEREFORE THE OXIDATION STATE OF NITROGEN IN NO2 IS 4
SIMILARLY ,
FOR (NO)
N+(-2)=0
N=2
FOR EXAMPLE
NO2 = OXIDATION STATE OF NITROGEN + 2* OXIDATION OF OXYGEN = 0 ( IT IS A RULE )
N + 2*(-2)=0
N - 4=0
N=4
THEREFORE THE OXIDATION STATE OF NITROGEN IN NO2 IS 4
SIMILARLY ,
FOR (NO)
N+(-2)=0
N=2
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0
Manganese. The most common oxidation states of the metal manganese are +2, +3, +4, +6, and +7; the +2 oxidation state is the most stable
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