Question

How to calculate rate of emission of quanta per second?

Answer 1

here is an example..

Powerof bulb, P= 25 Watt = 25 Js–1

Energyof one photon, E= hν 

Substitutingthe values in the given expression of E:



E =34.87 × 10–20 J

Rate ofemission of quanta per second



Answer 2

Step-by-step explanation:

h is planck's constant and its numerical value is 6.626×10−34 . Hence the obtained energy is , E=34.87×10−20J. And E is the energy which we have calculated. Hence the rate of emission of quanta per second is 7.17×1019 s−1