How to calculate the area of rectangle with one diagonal and breath?
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the diagonal and a length and a breadth will form a right angle triangle since each angle of a rectangle is of 90° so just the Pythagoras theorem , that is
hypotenuse² = base ²+perpendicular ²
the diagonal will be hypotenuse , consider breadth as base and length as perpendicular ( u can also consider length as base and breadth as perpendicular)
now write Pythagoras theorem as :-
-perpendicular ²= base²-hypotenuse²
perpendicular=√(-base²+hypotenuse ²)= length of the rectangle
we considered diagonal as the hypotenuse So now replace the hypotenuse with diagonal (both r same)
now area of rectangle will be breadth ×√(-base²+diagonal²)
hypotenuse² = base ²+perpendicular ²
the diagonal will be hypotenuse , consider breadth as base and length as perpendicular ( u can also consider length as base and breadth as perpendicular)
now write Pythagoras theorem as :-
-perpendicular ²= base²-hypotenuse²
perpendicular=√(-base²+hypotenuse ²)= length of the rectangle
we considered diagonal as the hypotenuse So now replace the hypotenuse with diagonal (both r same)
now area of rectangle will be breadth ×√(-base²+diagonal²)
Anonymous:
hope it was helpful
Answered by
0
The formula for calculating the area of rectangle with one diagonal and breadth is:
A = b √d^2– b^2
Hope this would help you.
Mark it as brainliest if u like.
@ Saadya
A = b √d^2– b^2
Hope this would help you.
Mark it as brainliest if u like.
@ Saadya
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