how to calculate the potential difference of 1.5V
Answers
Answered by
0
Number of electron density n = 8.4 x 10.
Are of cross section A = 0.3 mm2 =
0.3 x 10-6 m.
Charge of electron e = 1.6 x 10-19 C.
Applied electric field potential V = 1.5 V.
Hope it will helps ✌
Answered by
1
Answer:
The potential difference in a circuit is what causes current to flow through the circuit. ... Multiply the amount of the current by the amount of resistance in the circuit. The result of the multiplication will be the potential difference, measured in volts. This formula is known as Ohm's Law, V = IR.
Similar questions