How to catch multiple exceptions
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By using multiple catch blocks which can
handle different kinds of exception
class Example{
public static void main(String args[ ]){
try{
int arr[]=new int[7];
arr[4]=30/0;
System.out.println("Last Statement of try block");
}
catch(ArithmeticException e){
System.out.println("You should not divide a number by zero");
}
catch(ArrayIndexOutOfBoundsException e){
System.out.println("Accessing array elements outside of the limit");
}
catch(Exception e){
System.out.println("Some Other Exception");
}
System.out.println("Out of the try-catch block");
}
Hope it helps you!!!!
handle different kinds of exception
class Example{
public static void main(String args[ ]){
try{
int arr[]=new int[7];
arr[4]=30/0;
System.out.println("Last Statement of try block");
}
catch(ArithmeticException e){
System.out.println("You should not divide a number by zero");
}
catch(ArrayIndexOutOfBoundsException e){
System.out.println("Accessing array elements outside of the limit");
}
catch(Exception e){
System.out.println("Some Other Exception");
}
System.out.println("Out of the try-catch block");
}
Hope it helps you!!!!
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