Physics, asked by sudi6900, 1 year ago

How to catch multiple exceptions

Answers

Answered by deepu51175
0
By using multiple catch blocks which can

handle different kinds of exception

class Example{
public static void main(String args[ ]){
try{
int arr[]=new int[7];
arr[4]=30/0;
System.out.println("Last Statement of try block");
}
catch(ArithmeticException e){
System.out.println("You should not divide a number by zero");
}
catch(ArrayIndexOutOfBoundsException e){
System.out.println("Accessing array elements outside of the limit");
}
catch(Exception e){
System.out.println("Some Other Exception");
}
System.out.println("Out of the try-catch block");
}

Hope it helps you!!!!
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