Math, asked by monjyotiboro, 5 hours ago

How to check if this series is in AGP(Arithmetico Geometric progression) :



1+2x+3x^2+4x^3+...


Answers

Answered by user0888
8

The answer is attachment due to the inappropriate word.

Attachments:
Answered by LivetoLearn143
3

\large\underline{\sf{Solution-}}

The given series is

\rm :\longmapsto\:1 + 2x +  {3x}^{2} +  {4x}^{3}  +  -  -  -  -  -

is a product of corresponding terms of 2 series.

First series is

\rm :\longmapsto\:1,2,3,4, -  -  -  -

and

Second series is

\rm :\longmapsto\:1,x, {x}^{2} , {x}^{3} , -  -  -  -

Now,

Let we check the first series,

\rm :\longmapsto\:1,2,3,4, -  -  -  -

Since,

\rm :\longmapsto\:2 - 1 = 3 - 2 = 4 - 3 =  -  -

So, its an AP series

Now,

Let we check the second series,

\rm :\longmapsto\:1,x, {x}^{2} , {x}^{3} , -  -  -  -

Since,

\rm :\longmapsto\:\dfrac{x}{1}  = \dfrac{ {x}^{2} }{x}  = \dfrac{ {x}^{3} }{ {x}^{2} }  =  -  -

Therefore, its an GP series.

So, the given series is a product of corresponding terms of AP and GP, therefore its an AGP series.

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