Chemistry, asked by zinettadalmeida2633, 1 year ago

How to compare ease of liquefaction in 2 gases?

Answers

Answered by Sukhpreet85
0

By comparing their Z’s.

For real gases, we compare the value of Z, which is.

Z=(PV/nRT)

Z is itself called the compressibility factor.

Which is 1 for the ideal gas.

So, closer the value of Z to 1 easier will be the gas to liquify.

I hope this helped. Please contact for further doubts and details. I would love to help.

Thankyou

Answered by maahira589
1

Answer:

Gases can be liquified by applying pressure and lowering the temperature. ... On applying pressure the gaseous particles come closer and start attracting eachother. When gas is compressed too much then heat is produced due to compression.

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