Question

how to convert galvanometer into ammeter

Answer 1

Since Galvanometer is a very
sensitive instrument
therefore it can't measure
heavy currents. In order to
convert a Galvanometer into
an Ammeter , a very low
resistance known as "shunt"
resistance is connected in parallel to
Galvanometer. Value of shunt is so adjusted
that most of the current passes through the
shunt.

Answer 2

Answer:

--A galvanometer is a device that is used to detect small electric current or measure its magnitude.

--Ammeter is a device used to measure either alternating or direct current.

Concept:-

• A galvanometer can be coverted into an ammeter by connecting a shunt.
• [Shunt is a low resistance which connected parallel and allows only permissible current]
• When the shunt connected parallel with galvanometer it allows only permissible current.
• The shunt also does not affect the functioning part of the coil and measure part of the circuit.

Conversion:-

Let - G = Galvanometer resistance

S = Required shut

$\tt \: I_g= \sf \: current \: flowing \: \: through \: Galvanometer \:$

$\tt \: I_s= \sf \: current \: flowing \: through \: the \: shunt$

I = Total current flowing

I = Total current flowingSo,

$\: \: \: \: \: \: \: \: \: \: \: \tt \: I = I_g + I_s$

$\implies \: \tt \: I_s = I - I_g$

Since, The Galvanometer and shunt are in parallel combination, their terminal potential difference will be equal.

$\: \: \: \: \: \: \: \: \: \tt \: GI_g= S.I_s$

$\implies \tt \: S = \frac{GI_g}{I_s }$

$\boxed{ \boxed{\implies \tt \: S = \frac{GI_g}{I-I_g }} }$

If this ammount of shunt is added to the galvanometer then it becomes ammeter.

Note :-

A low resistance Galvanometer is an Ammeter.since its resistance is low it always connected series in the circuit.

Thank you :)