Question

how to derive 3rd equation of motion from the first two equations of motion?/

Answer 1

Answer:

2nd equation: S= ut + ½ at 2

1st equation: v=u+at

from 2nd equation we get that:

S= ½ (u+v)*t.......(eq-1)

from 1st equation we get that:

t=(v-u)/a......(eq-2)

from (eq-1) we get that:

=> S= ½ (u+v)*((v-u)/a)........(putting the value of t in this equation which we have got in (eq-2).)

=>S= ½((v^2-u^2)/a)

=>2aS=v^2-u^2

=>v^2=u^2+2aS.......3rd equation of motion derived.

Explanation:

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