how to derive Normal Form equation from general equation of straight line?
Answers
Answered by
7
Answer:
This is called the normal form of equation of the given line making the angle ø with the positive direction of x-axis and whose perpendicular distance from the origin is p. Thus, for converting the given line into normal form, divide the equation ax+by+c=0 by √(a2+b2).
Attachments:
Answered by
5
Then, we have Cos ø = p/m à m = p/Cos ø
And Sin ø = p/n à n = p/Sin ø
The equation of line in intercept form is,
x/m + y/n =1
x/(p/Cos ø) + y/(p/Sin ø) = 1
x Cos ø/p + y Sin ø/p =1
x Cos ø + y Sin ø = p.
This is called the normal form of equation of the given line making the angle ø with the positive direction of x-axis and whose perpendicular distance from the origin is p.
here is your answer
hope ur satisfied with the answer
Attachments:
Similar questions