How to determine the equivalent resistance of two resistors when connected in series?
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add both the resistor value to get the total resistance.
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Hi !
Let the resistances of the resistors be "R₁" and "R₂".
Let the total resistance be "R"
The current , I , passing through each of them is same.
But potential difference (p.d) across the two points of both the resistors is different
Let the p.d across R₁ be "V₁" and p.d across R₂ be "V₂"
Therefore , total p.d = V
V = V₁ + V₂
We know that , by Ohm's law :-
V = IR
So ,
V₁ = IR₁
V₂ = IR₂
we know that V = V₁ + V₂
so ,
IR = IR₁ + IR₂
Dividing throughout by "I"
R = R₁ + R₂
Hence , when resistors are connected in series , their total resistance is given by sum of the resistances of the resistors
Let the resistances of the resistors be "R₁" and "R₂".
Let the total resistance be "R"
The current , I , passing through each of them is same.
But potential difference (p.d) across the two points of both the resistors is different
Let the p.d across R₁ be "V₁" and p.d across R₂ be "V₂"
Therefore , total p.d = V
V = V₁ + V₂
We know that , by Ohm's law :-
V = IR
So ,
V₁ = IR₁
V₂ = IR₂
we know that V = V₁ + V₂
so ,
IR = IR₁ + IR₂
Dividing throughout by "I"
R = R₁ + R₂
Hence , when resistors are connected in series , their total resistance is given by sum of the resistances of the resistors
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