How to do: 6-x/x^2-4 = 2+ x/x+2 And how many solutions are there for this?
Answers
Answered by
1
WELL IT'S AN EASY ONE
(6-x)/(x^2-4)=(2+x)/(x+2)
(6-x)/(x^2-4)= 1
[b/c x+2 and 2+x is the same thing]
NOW
6-x = x^2-4
x^2+x-10=0
and hopefully you can find the solutions for this quadratic equation
(6-x)/(x^2-4)=(2+x)/(x+2)
(6-x)/(x^2-4)= 1
[b/c x+2 and 2+x is the same thing]
NOW
6-x = x^2-4
x^2+x-10=0
and hopefully you can find the solutions for this quadratic equation
Attachments:
iittssmmee88:
on the first step
Its actually 2+(x/x+2)
Please replyy...
okay wait
It was my mistake that i did not specify the brackets..
Sorryyy
no problem I just added a pic please
check it out
Thanksss
welcome
Similar questions