Question

How to do the 6th one

Answer 1

Solution :

Considering L.H.S

CosA/( 1 + SinA) + (1 + SinA)\CosA

⇒ [ Cos^2A + ( 1 + SinA)^2]  / CosA * ( 1 + SinA)

⇒ [ Cos^2A + 1 + Sin^2A + 2 SinA ] / CosA * ( 1 + SinA)

By Using the trigonometric theory

⇒( 1 + 1 + 2 SinA) / CosA * ( 1 + SinA)

⇒ 2( 1 + SinA)/CosA * ( 1 + SinA)

Sin A get cancel out

⇒ 2/CosA

We Know that ,

1/CosA = SecA

Then ,

⇒ 2/CosA

⇒ 2 SecA

Hence Proved  , R.H.S = L.H.S

Answer 2

hope this helps you............
pls mark as brainlist !!!!!!