Question

how to do this question​

Answer 1

Answer:

$\frac{2}{3} (y-5) - \frac{1}{4} (y-2) = \frac{9}{2}$

taking LCM on LHS

$\frac{8(y-5)-3(y-2)}{12} = \frac{9}{2}$

$\frac{8y-40-3y+6}{12} = \frac{9}{2}$

$\frac{5y-34}{12} = \frac{9}{2}$

$5y - 34 = \frac{108}{2}$

$5y = \frac{108}{2} - 34$

$5y = \frac{108-68}{2}$

$5y = \frac{40}{2}$

$5y = 20$

$y = 4$

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