Math, asked by blazingboy619, 1 year ago

how to draw a graph of line 2x-y=3

Answers

Answered by abhikumar12
0

Find a few (x, y) pairs that satisfy the equation; plot these points; connect them.

Explanation:

Pick some values for x , and use the equation to find what y must be for each of those x 's.

For example, if x is 0, then we have:

2x + y = 3

⇒ 2(0) + y = 3

⇒ 0 + y = 3

⇒ y = 3

So when x = 0 , we have y = 3 . Meaning the point

(x, y) = (0, 3) is a solution to 2x + y = 3 , and so our graph of the equation will pass through (0, 3) .

We can get a few more points:

If x = 1 , then

2x + y = 3

⇒ 2(1) + y = 3

⇒ 2 + y = 3

⇒ y = 1

So (x, y) = (1, 1) is also on our graph.

Similarly, if x = 2 , then we get y = –1 , giving us the point (x, y) = (2, –1) .

We then take the points we've computed,

(0, 3), (1, 1), (2, –1) , and plot them on a graph:

graph{((x)^2+(y-3)^2-.02)((x-1)^2+(y-1)^2-.02)((x-2)^2+(y+1)^2-.02)=0 [-10, 10, -5, 5]}

Last, since we know this equation is linear, we just need to connect the dots with a line:

graph{((x)^2+(y-3)^2-.02)((x-1)^2+(y-1)^2-.02)((x-2)^2+(y+1)^2-.02)(2x+y-3)=0 [-10, 10, -5, 5]}

And we're done!

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