Math, asked by ayushseth8498, 1 year ago

How to draw AOB=100°

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Answered by palakhkoyalkar06
0

HEY MATE

FOLLOW THE FOLLOWING STEPS ..

HEY MATE SORRY FOR NOT TYPING BUT HAVE SEND THE SCREEN SHOT OF I HAVE TYPED AS BRAINLY SAYING THEY ARE RUDE FOR ....AGAIN SORRY FOR INCONVENIENCE.

HOPE IT HELPS

HAVE A NICE DAY AHEAD. ....^ _ ^

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Answered by shadowsabers03
0

To draw an angle of 100° without using protractor...

1.   Construction of 120° angle (Fig. 1)

⇒  Draw a base line and mark a point A on the line.

⇒  Draw a semicircle over the line with center A of any radius. Mark the points of intersection of the semicircle and the line as B and C.

⇒  Cut the semicircle by an arc of same radius as that of the semicircle, with center C. Mark the point of intersection of the semicircle and the arc as D.

⇒  ∠BAD = 120°

2.   Angle trisection of 120° (Fig. 2, 3 & 4)

⇒   Draw a line from the point D towards the points F at the base line through a point E on the semicircle in such a way that AD = AE = EF. (Fig. 2)

For this, it is better to mark the length of AD at one end of a straightedge or a bond paper strip, which is also placed beside the point D.

  • Take a straightedge and mark the length of AD at one end of it.
  • Place the straightedge near the point D in such a way that the one end of the marking of the length of AD in the straightedge should be at the semicircle and the other end should be at the base line.
  • Mark the point where one end of AD marked in the straightedge meets the semicircle as E and that where the other end meets the base line as F.

⇒   Draw a line through the point A parallel to DF thus formed. Mark the point of intersection of this line and the semicircle as G. (Fig. 3)

⇒   ∠BAG = 40°

⇒   Bisect ∠GAD = 80°. (Fig. 4)

  • Draw two arcs over the semicircle with centers D and G each of radius the same as length of DG in such a way that these two arcs meet each other.
  • Mark the point of intersection of these arcs as H.
  • Join AH and mark the point of intersection of AH and the semicircle as I.
  • Thus ∠GAD = 80° is bisected and ∠BAD = 120° is trisected.

Now, ∠CAI = 100° (Fig. 5)

You can change the name ∠CAI and make it ∠AOB or anything else. This is a method of pure construction of 100° angle.

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