Question

How to evaluate limit lim tend to infinity 1/n (sin pi/n+sin2pie/n+ •••) as riemann sums?

Answer 1

Answer:

limn→∞(sinπ2n.sin2π2n.sin3π2n.....sin(n−1)π2n)1/n I was wondering,is there a formula for multiplication of sines,when angles are in arithmetic ...