how to express reccuring decimal number 0.55.... in the form of p by q where p and q are integers and q is not equal to zero
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Let X = 0.53
Then X = 0.5353 -------(1)
Multiply equation (1) by 100 we get,
100X = 53.5353 -------(2)
Subtract equation (1) from equation (2) we get,
100X = 53.5353
X = 0.5353
____________
99X = 53
X
Answered by
4
Answer:
x = 5/9
Step-by-step explanation:
Let x=0.555..... - 1equation
10x = 5.555..... - 2equation
subtract both the equations
10x - x = 5.555... - 0.555...
9x = 5
Therefore x = 5/9
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