How to factorise 1-2ab-(a^2-b^2)?
pids:
Please review your question....
hey it is not possible ,it is possible only when 1-2ab-(a^2+b^2)
Answers
Answered by
16
by simplifying
1 - 2ab - a² - b²
1 - (a² + 2ab + b²)
1 - (a + b)²
wkt , (a² - b²) = (a+b)(a-b)
as 1 = 1²
1² - (a+b)² = [1+(a+b)]*[1-(a+b)]
= (1+a+b)(1-a-b)
1 - 2ab - a² - b²
1 - (a² + 2ab + b²)
1 - (a + b)²
wkt , (a² - b²) = (a+b)(a-b)
as 1 = 1²
1² - (a+b)² = [1+(a+b)]*[1-(a+b)]
= (1+a+b)(1-a-b)
@Sweety...I think you should go through your answer once again...
1-2ab-(a^2-b^2)
1-2ab-(a^2-b^2)
on simplyfing... 1-2ab-a^2+b^2....so all the step goes wrong after..
sh*t sry i didn't see it ,let me check it
Answered by
5
I think this is to which I can factorize it...
cmplt it Mr.pids
Similar questions