Question

how to factorise: 6ab - b2 + 12ac - 2bc?

Answer 1

Hi ,.

6ab - b² + 12ac - 2bc

= 6ab + 12ac - b² - 2bc

= 6a( b + 2c ) - b( b + 2c )

= ( b + 2c ) ( 6a - b )

I hope this helps you.

: )

Answer 2

Answer:

$6ab-b^2+12ac-2bc=(6a-b)(b+2c)$

Step-by-step explanation:

Given the expression

$6ab-b^2+12ac-2bc$

we have to factorize the above expression

$6ab-b^2+12ac-2bc$

$6ab+12ac-b^2-2bc$

$6a(b+2c)-b(b+2c)$

$(6a-b)(b+2c)$

which is required factorization.