Math, asked by YashitaYadav, 3 months ago

How to factorise (a² +96² - 6ab)- 4 c²

Answers

Answered by anmita18

0

Answer:

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(a² + 9b² - 6ab) - 4c²

[ a² + (3b)²-2(3ab)] - 4c²

(a-3b)² - 4c²

Therefore,

(a-3b)² - (2c)²

a²-b² = (a+b)(a-b)

(a-3b+2c)(a-3b-2c)

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