How to factorise the cubic polynomial y cube + 13 y square + 32 y + 20
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Answered by
1
Answer:
Step-by-sLet p (x) = y^3 + 13y^2 +32y + 20
Using hit and trial method
y= -1
p (-1) = -1 + 13 -32 +20
=-33+ 33
= 0
So, (y +1 ) is a factor of p (y) [by factor theorem]
To fing other factors we must divide p (y) by (y+1)
And the other factor found is y^2 +12y + 10
Factorising y^2 +12y +20
= y^2 +10y + 2y +20
= y (y +10) +2 (y +10)
= (y+2)(y+10)
So, polynomial p (y) would be factorised as (y+2)(y +10)(y+1).
Answered by
0
Step-by-step explanation:
y cube ➕ 13 square ➕ 12y ➕ 20y ➕ 20
y cube ➕ y square ➕ 12y square ➕ 12y ➕ 20y ➕ 20
y square(y ➕ 1) ➕ 12(y ➕ 1) ➕ 20(y ➕ 1)
(y ➕ 1) (y square ➕12y ➕ 20)
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