Math, asked by yassermarvel, 9 months ago

A ball is thrown up ward with a speed of 10m/s. Calculate the speed of the ball after 1s.​

Answers

Answered by Ral123
0

V=U-gt

Substituting values

V=10-10x1

=10-10=0m/s

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Answered by shaharbanupp
0

Answer:

A ball is thrown upward with a speed of 10m/s. The speed of the ball after 1s will be 0.2 m/s

Step-by-step explanation:

  • From the question,

       The initial speed of the body = 10m/s

       The time is taken = 1 s

  • We can solve this problem using the first equation of motion.

        It is given by,

        V = u+at    ...(1)

       Where Vis the final velocity of the body, u is the initial velocity, a is the acceleration due to gravity, and tis the time taken by the body.

  • since the body is thrown upwards.

        a = -g

        We know g is the acceleration due to gravity

        g= 9.8m/s^2

Substitute these values into equation (1)

V = 10-(9.8\times 1)

    =0.2 m/s

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