How to factorise the term 6-x-x^2
Answers
Answered by
2
Hey dear!
Here is yr answer.....
=> 6 - x - x²
=> 6 + 2x - 3x - x²
=> 2(3+x) -x(3+x)
=> (3+x) (2-x)
Hope it hlpz...
Here is yr answer.....
=> 6 - x - x²
=> 6 + 2x - 3x - x²
=> 2(3+x) -x(3+x)
=> (3+x) (2-x)
Hope it hlpz...
Answered by
7
Hey there!
6-x-x²
= -x² - x + 6
By splitting the middle term, it gotta be
-x² + 2x - 3x + 6
-x (x - 2) -3 (x -2)
(-x - 3) (x - 2)
(x + 3) (x - 2)
Glad If helped!
6-x-x²
= -x² - x + 6
By splitting the middle term, it gotta be
-x² + 2x - 3x + 6
-x (x - 2) -3 (x -2)
(-x - 3) (x - 2)
(x + 3) (x - 2)
Glad If helped!
Anonymous:
(x-2) didi
edited ;)
^_^
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