Question

How to factorize x -8xy3 on the basis of  (x3 - y3) ?

Answer 1

HEY!!

x – 8xy3
= x (1 – 8y3)
= x [(1)3 – (2y)3]
= x (1 – 2y) [(1)2 + 1 × (2y) + (2y)2] [ a3 – b3 = (a – b) (a2 + ab + b2)]
= x (1 – 2y) (1 + 2y + 4y2)
Thus, x – 8xy3 can be factorized as x (1 – 2y) (1 + 2y + 4y2).

Answer 2

Hello friends..

Here is ur answer :


$x - 8x {y}^{3}$


$x(1 - 8 {y}^{3} )$


$x( {(1)}^{3} - {(2y)}^{3} )$

Using identity :

${x}^{3} - {y}^{3} = (x - y)( {x}^{2} + {y}^{2} + xy)$


$x(1 - 2y)( {(1)}^{2} + {(2y)}^{2} + (1)(2y))$


$x(1 - 2y)(1 + 4y + 2y)$


HOPE IT HELPS..