Question

How to find 18th term of AP root 2 root 18 root 50 root 98

Answer 1

Hope this helps you....✌

Answer 2

The 18th term of the given AP is 35$\sqrt2$.

Step-by-step explanation:

The given AP can be rewritten as $\sqrt2, 3\sqrt2, 5\sqrt2, 7\sqrt2$….

Here,

First term = a = $\sqrt2$

Common difference = d $= 3\sqrt2 - \sqrt2 = 2\sqrt2$

To find:

18th term, ∴ n = 18

Using the formula for finding nth term of an A.P.,

$a_n = a + (n - 1) \times d$

∴ $a_{18} = \sqrt2 + (18 - 1) \times 2\sqrt2$

⇒ $a_{18} = \sqrt2 + 17 \times 2\sqrt2 = \sqrt2 + 34\sqrt2 = 35\sqrt2$

∴ 18th term of the given AP is 35$\sqrt2$.