how to find (2x+3y-3)^2?
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it is on the formula (a+b+c)² .so put this in this formula
(a²+b²+c²+2ab+2bc+2ac)
={(2x)²+(3y)²+(-3)²+2×2x×3y+2×3y×-3+2×2x×-3}
=4x²+9y²+9+12xy-18y-12x
(a²+b²+c²+2ab+2bc+2ac)
={(2x)²+(3y)²+(-3)²+2×2x×3y+2×3y×-3+2×2x×-3}
=4x²+9y²+9+12xy-18y-12x
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