Question

How to find a altitude of triangle whose base is15cm,and the two side are 13cm, 14cm

Answer 1

Answer :-

Step by step :-

Area of triangle :-

Semi perimeter =

$= \frac{15 + 13 + 14}{2} = 21cm$ \\

$= \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \sqrt{21 \times 6 \times 8 \times 7} \\ \\ = \sqrt{7 \times 3 \times 2 \times 3 \times 2 \times 4 \times 7} \\ \\ = 84 {cm}^{2}$

We know that area of triangle.

= 1/2 × base × hieght

Base is given 15 cm.

$\frac{1}{2} \times 15 \times h = 84 \\ \\ h = \frac{84 \times 2}{15} = 11.2cm$

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Answer 2

the answer of altitude is 11.4 cm