Question

HOW TO FIND A CUBIC POLYNOMIAL​

Answer 1

Step-by-step explanation:

${x}^{3} - {x}^{2} ( \alpha + \beta + \gamma ) + x( \alpha \beta + \beta \gamma + \gamma \alpha ) - \alpha \beta \gamma \\ \\ mark \: me \: as \: brainliest$

formula is ax^3+bx^2+cx+d

Answer 2

Answer:

$let \: \alpha \: and. \beta \: \:and \: \gamma \: be the \: zeroes \: of \: the \: cubic \: polynomial \: \\ then \: required \: cubic \: polynomial \: \: is \\ {x}^{3} - ( \alpha + \beta + \gamma ) {x}^{2} + ( \alpha \beta + \beta \gamma + \gamma \alpha )x - \alpha \beta \gamma = 0.$