How to find angle OTS
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∠OTS = 180° - a - b/2 (where a and b are given but hard to read).
I think they're a = 25° and b = 127°, in which case,
∠OTS = 180° - 25° - 63.5° = 91.5°.
Of course, if I've misread the numbers, you'll have to fix that bit up.
Hope that helps!
Step-by-step explanation:
Let x = ∠OTS.
Triangle OTS is isosceles since OT = OS are radii. So ∠OST = ∠OTS = x.
I'm not sure I can read the numbers correctly in the photo, so for the moment, put a = ∠OPS and b = ∠POT. These are the given angles in the diagram, so we want x in terms of a and b.
As above, triangle OPS is also isosceles, so ∠OSP = ∠OPS = a.
The sum of the interior angles of the quadrilateral OPST is 360°, so
a + b + x + ( a + x ) = 360°
=> 2x = 360° - 2a - b
=> x = 180° - a - b/2.
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