how to find AP
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Given,
P = (2,2)
A= (-2,k)
B= (-2k,-3)
Now Given that point P is equidistant from A and P
We now that if two points are (x1, y1) and (x2,y2 ) ,
Then distance between them=
√{(x1-x2)² + (y1-y2)²}
Similarly find the AP and BP and equal them as mentioned in question,
Refer to picture
P = (2,2)
A= (-2,k)
B= (-2k,-3)
Now Given that point P is equidistant from A and P
We now that if two points are (x1, y1) and (x2,y2 ) ,
Then distance between them=
√{(x1-x2)² + (y1-y2)²}
Similarly find the AP and BP and equal them as mentioned in question,
Refer to picture
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