how to find area and the perimeter of a square whose diagnol is 10cm by pythagorus method
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the diagonal of a square divide the square into two equal triangles so
take the length of side=x
according to phytagorus therom hypotneus square=side square+side square so
diagonal square=side square+side square
in a square sides are equal in length so
diagonal square=2×side square
10square=2x square
100=2x square
after solving
side of square=5cm
perimeter=20cm
area=25cm
take the length of side=x
according to phytagorus therom hypotneus square=side square+side square so
diagonal square=side square+side square
in a square sides are equal in length so
diagonal square=2×side square
10square=2x square
100=2x square
after solving
side of square=5cm
perimeter=20cm
area=25cm
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