Question

how to find area of trapezium whose parallel sides is 15 CM and height is 4 cm​

Answer 1

Answer:

Solution:

Let the common ration be x,

Then the two parallel sides are 3x, 2x

Distance between them = 10 cm

Area of trapezium = 325 cm²

Area of trapezium = 1/2 (p₁ + p₂) h

325 = 1/2 (3x + 2x) 10

⇒ 325 = 5x × 5

⇒ 325 = 25x

⇒ x = 325/25

Therefore, 3x = 3 × 13 = 39 and 2x = 2 × 13 = 26

Therefore, the length of parallel sides area are 26 cm and 39 cm.

Answer 2

Answer:

In ΔCEF, CE = 10 cm and EF = 6cm Using Pythagoras theorem: CE2 = CF2 + EF2 CF2 = CE2 – EF2 CF2 = 152 – 62 CF2 = 225-36 CF2 = 189 CF = √189 = √ (9×21) = 3√21 cm From the figure we can write, Area of trapezium = Area of parallelogram AECD + Area of area of triangle CEF Area of trapezium = height + 1/2 (sum of parallel sides) Area of trapezium = 3√21 × 1/2 (25 + 13) Area of trapezium = 3√21 × 19 = 57√21